combs = [] list1 = [1,2,3] list2 = [3,1,4] for x in list1: for y in list2: if x != y: combs.append((x, y)) print(combs) print(combs[2][0]) print(combs[2][1])
results in:
[(1, 3), (1, 4), (2, 3), (2, 1), (2, 4), (3, 1), (3, 4)] 2 3
But there’s also a more elegant solution using list comprehensions:
list1 = [1,2,3] list2 = [3,1,4] combs2 = [(x, y) for x in list1 for y in list2 if x != y] print(combs2)